15v^2-18=-3v

Solution for 15v^2-18=-3v equation:

15v^2-18=-3v

We move all terms to the left:

15v^2-18-(-3v)=0

We get rid of parentheses

15v^2+3v-18=0

a = 15; b = 3; c = -18;
Δ = b2-4ac
Δ = 32-4·15·(-18)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*15}=\frac{-36}{30}
=-1+1/5
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*15}=\frac{30}{30}
=1
$